select * from members m where m.member_firstname like 'Josef'
select * from members m where m.member_active = true and m.member_count = 0;

update members
set member_email = null
where member_email = ''

select * from members order by members.updated_date  desc

update members m set member_geo_latitude = null, member_geo_longitude = null
where id in (110,107,45,21,19,108,36,24,22,18,35,162,90,3,142,122,121,115,9,128,79,78,50,186,183,180,176,157,148,98);

select * from members m where m.member_geo_latitude is null;

select * from members m where id in (110,107,45,21,19,108,36,24,22,18,35,162,90,3,142,122,121,115,9,128,79,78,50,186,183,180,176,157,148,98);

update members m set member_geo_latitude = null, member_geo_longitude = null

ALTER TABLE sust.deliveries ADD CONSTRAINT deliveries_member_id_delivered_by_fkey FOREIGN KEY (delivered_by_id) REFERENCES members(id)

update deliveries set delivered_by_id = 186

update members set member_city = 'Sankt Thomas' where member_city = 'St. Thomas'

update members set member_city = trim(member_city)

insert into deliveries (delivery_date, member_id, delivered_by_id, delivery_year)
values (now(), 204, 186, '2025-01-01') --,
	   (now(), 79, 186, '2024-01-01'),
	   (now(),  3, 186, '2024-01-01'),
	   (now(),  4, 186, '2024-01-01'),
	   (now(),  9, 186, '2024-01-01')
	   
insert into deliveries (delivery_date, member_id, delivered_by_id, delivery_year)
values (now(), 8, 186, '2024-02-21')

select count(*) from deliveries d

update deliveries set delivery_year = '2024-01-01'

create table sust.payments_csv
(id serial, 
 pc_valuta_date date,
 pc_client varchar(50),
 pc_reference varchar(50), 
 pc_intended varchar(50),
 pc_iban varchar(50), 
 pc_entry_date date, 
 pc_amount money, 
 pc_currency varchar(3),
 pc_timestamp timestamp)
 
COPY payments_csv(pc_valuta_date, pc_client, pc_reference, pc_intended, pc_iban, pc_entry_date, pc_amount, pc_currency, pc_timestamp)
FROM 'C:\Users\zisco\OneDrive\Dokumente\SUST\UmsatzListe_AT493443700000113407_v1.csv'
DELIMITER ';'
CSV HEADER;
 
CREATE UNIQUE INDEX payments_ukey_member_year ON sust.payments USING btree (member_id, payment_year)

select count(*) from payments_csv where pc_processed = true
select  from payments_csv where pc_processed = false

select * from payments_csv pc where PC.pc_client like '%Anna%';
select * from members mem where mem.member_firstname like 'Anna%';
select * from payments p where p.member_id = 58;  

ALTER TABLE payments_csv ADD PRIMARY KEY (id);

select * from payments p where p.member_id in (205,206);
select * from payments p where date_part('year', p.payment_year) = 2025;

select * from payments_csv where pc_processed = false;

select pc.pc_reference from payments_csv pc where pc_processed =false order by pc_reference asc 

select m.member_surname, m.member_firstname, m.member_firstname_spouse from members m
except
select mp.member_surname, mp.member_firstname, mp.member_firstname_spouse from members_paid mp

select * from members_paid mp where id = 8

SELECT ma.*, m.member_suffix, m.member_email
FROM members_active ma
JOIN members m ON m.id = ma.id
-- WHERE m.member_email IS NOT NULL 
-- AND TRIM(m.member_email) <> ''
ORDER BY m.member_surname, m.member_firstname;


-- already delivered
select m.*, d.*
from members_active m 
right join deliveries d on d.member_id = m.id 
where d.delivery_year = '2025-01-01'
order by delivery_date asc

select * from deliveries d 
where d.delivery_year = '2025-01-01'

insert into deliveries (delivery_date, member_id, delivery_year)
select now(), ss.id, '2024-01-01' from
(select id from members_active m 
except
select member_id from deliveries d) ss

select count(*) from deliveries d

-- already paid?
SELECT m.*
FROM members_active m
JOIN deliveries d ON d.member_id = m.id
WHERE m.id IN (
    SELECT md.id 
    FROM members_delivered md
    EXCEPT
    SELECT mp.id 
    FROM members_paid mp 
    WHERE mp.payment_year IN ('2024-01-01', '2025-01-01')
)
ORDER BY m.member_surname, m.member_firstname, d.delivery_date ASC;

SELECT id
FROM members_active
WHERE member_email is Null
    AND id NOT IN (
    SELECT member_id FROM (
        VALUES (116), (26), (65), (66), (70), (8), (88), (130), (146), (163), (195),
               (76), (120), (125), (126), (131), (136), (143), (151), (152), (160),
               (166), (170), (172), (179), (196), (34), (40), (41), (42), (47),
               (52), (71), (147), (194), (124), (178), (23), (123), (144), (168),
               (182), (198), (31), (33), (43), (58), (75), (94), (100), (108), (11),
               (111), (115), (117), (118), (119), (122), (127), (128), (13), (138),
               (141), (148), (15), (153), (158), (159), (16), (161), (162), (165),
               (169), (171), (175), (176), (177), (18), (180), (181), (19), (192),
               (193), (2), (202), (204), (205), (24), (27), (28), (29), (3), (30),
               (35), (36), (4), (46), (48), (5), (59), (6), (61), (62), (63), (68),
               (77), (78), (79), (80), (81), (83), (84), (86), (87), (9), (90),
               (92), (93), (95), (96), (97), (98), (99), (203)
    ) AS extracted_members(member_id)
);

-- Members active in 2025 but haven't paid for 2025
SELECT m.*
FROM members_active m
WHERE m.id NOT IN (
    SELECT mp.id 
    FROM members_paid mp 
    WHERE mp.payment_year = '2025-01-01'
    AND mp.id IS NOT NULL
)
ORDER BY m.member_surname, m.member_firstname;