Several enhancements
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+51
-10
@@ -1,4 +1,12 @@
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select * from members m where m.member_firstname like 'Josef'
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select * from members m where m.member_active = true and m.member_count = 0;
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update members
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set member_email = null
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where member_email = ''
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select * from members order by members.updated_date desc
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update members m set member_geo_latitude = null, member_geo_longitude = null
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where id in (110,107,45,21,19,108,36,24,22,18,35,162,90,3,142,122,121,115,9,128,79,78,50,186,183,180,176,157,148,98);
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@@ -53,7 +61,7 @@ select count(*) from payments_csv where pc_processed = true
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select * from payments_csv pc where PC.pc_client like '%Anna%';
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select * from members mem where mem.member_firstname like '%Anna%';
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select * from members mem where mem.member_firstname like 'Anna%';
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select * from payments p where p.member_id = 58;
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ALTER TABLE payments_csv ADD PRIMARY KEY (id);
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@@ -69,14 +77,13 @@ select mp.member_surname, mp.member_firstname, mp.member_firstname_spouse from m
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select * from members_paid mp where id = 8
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-- already paid? TODO: Member "active since?" attribute missing in "member"
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select m.*
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from members_active m
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join deliveries d on d.member_id = m.id
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where m.id in (select id from members_delivered md
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except
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select id from members_paid mp where mp.payment_year = '2024-01-01')
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order by delivery_date asc
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SELECT ma.*, m.member_suffix, m.member_email
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FROM members_active ma
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JOIN members m ON m.id = ma.id
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-- WHERE m.member_email IS NOT NULL
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-- AND TRIM(m.member_email) <> ''
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ORDER BY m.member_surname, m.member_firstname;
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-- already delivered
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select m.*, d.*
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@@ -94,4 +101,38 @@ select now(), ss.id, '2024-01-01' from
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except
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select member_id from deliveries d) ss
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select count(*) from deliveries d
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select count(*) from deliveries d
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-- already paid?
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SELECT m.*
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FROM members_active m
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JOIN deliveries d ON d.member_id = m.id
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WHERE m.id IN (
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SELECT md.id
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FROM members_delivered md
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EXCEPT
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SELECT mp.id
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FROM members_paid mp
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WHERE mp.payment_year IN ('2024-01-01', '2025-01-01')
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)
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ORDER BY m.member_surname, m.member_firstname, d.delivery_date ASC;
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SELECT id
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FROM members_active
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WHERE member_email is Null
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AND id NOT IN (
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SELECT member_id FROM (
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VALUES (116), (26), (65), (66), (70), (8), (88), (130), (146), (163), (195),
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(76), (120), (125), (126), (131), (136), (143), (151), (152), (160),
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(166), (170), (172), (179), (196), (34), (40), (41), (42), (47),
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(52), (71), (147), (194), (124), (178), (23), (123), (144), (168),
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(182), (198), (31), (33), (43), (58), (75), (94), (100), (108), (11),
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(111), (115), (117), (118), (119), (122), (127), (128), (13), (138),
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(141), (148), (15), (153), (158), (159), (16), (161), (162), (165),
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(169), (171), (175), (176), (177), (18), (180), (181), (19), (192),
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(193), (2), (202), (204), (205), (24), (27), (28), (29), (3), (30),
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(35), (36), (4), (46), (48), (5), (59), (6), (61), (62), (63), (68),
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(77), (78), (79), (80), (81), (83), (84), (86), (87), (9), (90),
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(92), (93), (95), (96), (97), (98), (99), (203)
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) AS extracted_members(member_id)
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);
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